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11025133000543 is a prime number
BaseRepresentation
bin1010000001101111110100…
…1000101101011101011111
31110000222210110211101120101
42200123331020231131133
52421113433022004133
635240513131001531
72215353034153354
oct240337510553537
943028713741511
1011025133000543
113570807177242
1212a08b28992a7
1361c8863869cc
142a189546062b
15141bc7d9e37d
hexa06fd22d75f

11025133000543 has 2 divisors, whose sum is σ = 11025133000544. Its totient is φ = 11025133000542.

The previous prime is 11025133000517. The next prime is 11025133000547. The reversal of 11025133000543 is 34500033152011.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11025133000543 - 213 = 11025132992351 is a prime.

It is a super-3 number, since 3×110251330005433 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11025133000547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5512566500271 + 5512566500272.

It is an arithmetic number, because the mean of its divisors is an integer number (5512566500272).

Almost surely, 211025133000543 is an apocalyptic number.

11025133000543 is a deficient number, since it is larger than the sum of its proper divisors (1).

11025133000543 is an equidigital number, since it uses as much as digits as its factorization.

11025133000543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 11025133000543 its reverse (34500033152011), we get a palindrome (45525166152554).

The spelling of 11025133000543 in words is "eleven trillion, twenty-five billion, one hundred thirty-three million, five hundred forty-three", and thus it is an aban number.