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11030000983 is a prime number
BaseRepresentation
bin10100100010111000…
…00111010101010111
31001110200220002211221
422101130013111113
5140042140012413
65022255111211
7540222314161
oct122134072527
931420802757
1011030000983
114750169aa1
122179b12507
13106a1ccc01
14768c7d931
1544851868d
hex291707557

11030000983 has 2 divisors, whose sum is σ = 11030000984. Its totient is φ = 11030000982.

The previous prime is 11030000959. The next prime is 11030001019. The reversal of 11030000983 is 38900003011.

11030000983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11030000983 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11030000903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515000491 + 5515000492.

It is an arithmetic number, because the mean of its divisors is an integer number (5515000492).

Almost surely, 211030000983 is an apocalyptic number.

11030000983 is a deficient number, since it is larger than the sum of its proper divisors (1).

11030000983 is an equidigital number, since it uses as much as digits as its factorization.

11030000983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 11030000983 its reverse (38900003011), we get a palindrome (49930003994).

The spelling of 11030000983 in words is "eleven billion, thirty million, nine hundred eighty-three", and thus it is an aban number.