Base | Representation |
---|---|
bin | 1010000010000001111111… |
… | …1101000000100111011010 |
3 | 1110001110101111201111001121 |
4 | 2200200133331000213122 |
5 | 2421203431044300010 |
6 | 35243041223035454 |
7 | 2215614660641266 |
oct | 240403775004732 |
9 | 43043344644047 |
10 | 11030012103130 |
11 | 357289030a229 |
12 | 12a183489bb8a |
13 | 620183166067 |
14 | 2a1bd94510a6 |
15 | 141db13c43da |
hex | a081ff409da |
11030012103130 has 64 divisors (see below), whose sum is σ = 19952897868288. Its totient is φ = 4390098718720.
The previous prime is 11030012103109. The next prime is 11030012103139. The reversal of 11030012103130 is 3130121003011.
It is a super-3 number, since 3×110300121031303 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (11030012103139) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5971851867 + ... + 5971853713.
It is an arithmetic number, because the mean of its divisors is an integer number (311764029192).
Almost surely, 211030012103130 is an apocalyptic number.
11030012103130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11030012103130 is a deficient number, since it is larger than the sum of its proper divisors (8922885765158).
11030012103130 is a wasteful number, since it uses less digits than its factorization.
11030012103130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4911.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11030012103130 its reverse (3130121003011), we get a palindrome (14160133106141).
The spelling of 11030012103130 in words is "eleven trillion, thirty billion, twelve million, one hundred three thousand, one hundred thirty".
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