Base | Representation |
---|---|
bin | 1010000010000011011110… |
… | …1110110101100111111101 |
3 | 1110001111102022101122022112 |
4 | 2200200313232311213331 |
5 | 2421210240211310102 |
6 | 35243144553423405 |
7 | 2215630603601255 |
oct | 240406756654775 |
9 | 43044368348275 |
10 | 11030411041277 |
11 | 3572a7551a381 |
12 | 12a192640ab65 |
13 | 6202179c5234 |
14 | 2a1c3641a965 |
15 | 141dd6428252 |
hex | a0837bb59fd |
11030411041277 has 2 divisors, whose sum is σ = 11030411041278. Its totient is φ = 11030411041276.
The previous prime is 11030411041201. The next prime is 11030411041283. The reversal of 11030411041277 is 77214011403011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6479437884676 + 4550973156601 = 2545474^2 + 2133301^2 .
It is a cyclic number.
It is not a de Polignac number, because 11030411041277 - 242 = 6632364530173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11030411041577) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515205520638 + 5515205520639.
It is an arithmetic number, because the mean of its divisors is an integer number (5515205520639).
Almost surely, 211030411041277 is an apocalyptic number.
It is an amenable number.
11030411041277 is a deficient number, since it is larger than the sum of its proper divisors (1).
11030411041277 is an equidigital number, since it uses as much as digits as its factorization.
11030411041277 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4704, while the sum is 32.
Adding to 11030411041277 its reverse (77214011403011), we get a palindrome (88244422444288).
The spelling of 11030411041277 in words is "eleven trillion, thirty billion, four hundred eleven million, forty-one thousand, two hundred seventy-seven".
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