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1103120147 is a prime number
BaseRepresentation
bin100000111000000…
…0100011100010011
32211212201022100202
41001300010130103
54224344321042
6301243405415
736223236503
oct10160043423
92755638322
101103120147
11516756548
1226952386b
13147703c1c
14a6711a03
1566ca0632
hex41c04713

1103120147 has 2 divisors, whose sum is σ = 1103120148. Its totient is φ = 1103120146.

The previous prime is 1103120143. The next prime is 1103120149. The reversal of 1103120147 is 7410213011.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1103120147 - 22 = 1103120143 is a prime.

Together with 1103120149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1103120143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551560073 + 551560074.

It is an arithmetic number, because the mean of its divisors is an integer number (551560074).

Almost surely, 21103120147 is an apocalyptic number.

1103120147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1103120147 is an equidigital number, since it uses as much as digits as its factorization.

1103120147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 20.

The square root of 1103120147 is about 33213.2525808599. The cubic root of 1103120147 is about 1033.2552139926.

Adding to 1103120147 its reverse (7410213011), we get a palindrome (8513333158).

The spelling of 1103120147 in words is "one billion, one hundred three million, one hundred twenty thousand, one hundred forty-seven".