Base | Representation |
---|---|
bin | 11001000101010001011110… |
… | …011111011110101101111111 |
3 | 112110120212111020210022202210 |
4 | 121011101132133132231333 |
5 | 103424334044441403210 |
6 | 1030341200043551503 |
7 | 32143613665116351 |
oct | 3105213637365577 |
9 | 473525436708683 |
10 | 110313525341055 |
11 | 32170781207403 |
12 | 1045760052b593 |
13 | 49726a028a34a |
14 | 1d352bb4bd0d1 |
15 | cb47944e4e20 |
hex | 64545e7deb7f |
110313525341055 has 64 divisors (see below), whose sum is σ = 191320859271168. Its totient is φ = 54059685980160.
The previous prime is 110313525341039. The next prime is 110313525341077. The reversal of 110313525341055 is 550143525313011.
It is not a de Polignac number, because 110313525341055 - 24 = 110313525341039 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 20764237 + ... + 25529993.
It is an arithmetic number, because the mean of its divisors is an integer number (2989388426112).
Almost surely, 2110313525341055 is an apocalyptic number.
110313525341055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
110313525341055 is a deficient number, since it is larger than the sum of its proper divisors (81007333930113).
110313525341055 is a wasteful number, since it uses less digits than its factorization.
110313525341055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4767936.
The product of its (nonzero) digits is 135000, while the sum is 39.
The spelling of 110313525341055 in words is "one hundred ten trillion, three hundred thirteen billion, five hundred twenty-five million, three hundred forty-one thousand, fifty-five".
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