Base | Representation |
---|---|
bin | 1010000010000111010011… |
… | …0001110100001110101011 |
3 | 1110001121001200120221002121 |
4 | 2200201310301310032223 |
5 | 2421214334404412141 |
6 | 35243434341412111 |
7 | 2215665151224454 |
oct | 240416461641653 |
9 | 43047050527077 |
10 | 11031435232171 |
11 | 3573450666132 |
12 | 12a1b7140a037 |
13 | 62034bc52253 |
14 | 2a1cd246412b |
15 | 141e462d71d1 |
hex | a0874c743ab |
11031435232171 has 2 divisors, whose sum is σ = 11031435232172. Its totient is φ = 11031435232170.
The previous prime is 11031435232117. The next prime is 11031435232273. The reversal of 11031435232171 is 17123253413011.
It is a happy number.
Together with previous prime (11031435232117) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is an emirp because it is prime and its reverse (17123253413011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11031435232171 - 219 = 11031434707883 is a prime.
It is not a weakly prime, because it can be changed into another prime (11031435232471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5515717616085 + 5515717616086.
It is an arithmetic number, because the mean of its divisors is an integer number (5515717616086).
Almost surely, 211031435232171 is an apocalyptic number.
11031435232171 is a deficient number, since it is larger than the sum of its proper divisors (1).
11031435232171 is an equidigital number, since it uses as much as digits as its factorization.
11031435232171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 34.
Adding to 11031435232171 its reverse (17123253413011), we get a palindrome (28154688645182).
The spelling of 11031435232171 in words is "eleven trillion, thirty-one billion, four hundred thirty-five million, two hundred thirty-two thousand, one hundred seventy-one".
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