Base | Representation |
---|---|
bin | 1010000010001001011100… |
… | …1110100110001101101001 |
3 | 1110001122112222010212000222 |
4 | 2200202113032212031221 |
5 | 2421222030334433111 |
6 | 35244011545335425 |
7 | 2216015400001511 |
oct | 240422716461551 |
9 | 43048488125028 |
10 | 11032013202281 |
11 | 3573717937685 |
12 | 12a20b2a97575 |
13 | 6204119067b6 |
14 | 2a1d49114841 |
15 | 141e7be027db |
hex | a08973a6369 |
11032013202281 has 2 divisors, whose sum is σ = 11032013202282. Its totient is φ = 11032013202280.
The previous prime is 11032013202277. The next prime is 11032013202307. The reversal of 11032013202281 is 18220231023011.
It is an a-pointer prime, because the next prime (11032013202307) can be obtained adding 11032013202281 to its sum of digits (26).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10722088291600 + 309924910681 = 3274460^2 + 556709^2 .
It is an emirp because it is prime and its reverse (18220231023011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11032013202281 - 22 = 11032013202277 is a prime.
It is a super-2 number, since 2×110320132022812 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11032013202281.
It is not a weakly prime, because it can be changed into another prime (11032013202211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516006601140 + 5516006601141.
It is an arithmetic number, because the mean of its divisors is an integer number (5516006601141).
Almost surely, 211032013202281 is an apocalyptic number.
It is an amenable number.
11032013202281 is a deficient number, since it is larger than the sum of its proper divisors (1).
11032013202281 is an equidigital number, since it uses as much as digits as its factorization.
11032013202281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 11032013202281 its reverse (18220231023011), we get a palindrome (29252244225292).
The spelling of 11032013202281 in words is "eleven trillion, thirty-two billion, thirteen million, two hundred two thousand, two hundred eighty-one".
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