11032013202307 has 2 divisors, whose sum is σ = 11032013202308. Its totient is φ = 11032013202306.

The previous prime is 11032013202281. The next prime is 11032013202311. The reversal of 11032013202307 is 70320231023011.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (70320231023011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11032013202307 - 2¹¹ = 11032013200259 is a prime.

It is not a weakly prime, because it can be changed into another prime (11032013202407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516006601153 + 5516006601154.

It is an arithmetic number, because the mean of its divisors is an integer number (5516006601154).

Almost surely, 2^{11032013202307} is an apocalyptic number.

11032013202307 is a deficient number, since it is larger than the sum of its proper divisors (1).

11032013202307 is an equidigital number, since it uses as much as digits as its factorization.

11032013202307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 11032013202307 its reverse (70320231023011), we get a palindrome (81352244225318).

The spelling of 11032013202307 in words is "eleven trillion, thirty-two billion, thirteen million, two hundred two thousand, three hundred seven".