Base | Representation |
---|---|
bin | 1010000010001010100011… |
… | …1111010010101010101111 |
3 | 1110001200022201211200112222 |
4 | 2200202220333102222233 |
5 | 2421223133130224301 |
6 | 35244101312145555 |
7 | 2216025645526205 |
oct | 240425077225257 |
9 | 43050281750488 |
10 | 11032311179951 |
11 | 357386005a716 |
12 | 12a21768382bb |
13 | 62045b576c49 |
14 | 2a1d7691d075 |
15 | 141e9816231b |
hex | a08a8fd2aaf |
11032311179951 has 2 divisors, whose sum is σ = 11032311179952. Its totient is φ = 11032311179950.
The previous prime is 11032311179921. The next prime is 11032311179959. The reversal of 11032311179951 is 15997111323011.
11032311179951 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11032311179951 - 210 = 11032311178927 is a prime.
It is a super-3 number, since 3×110323111799513 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11032311179959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516155589975 + 5516155589976.
It is an arithmetic number, because the mean of its divisors is an integer number (5516155589976).
Almost surely, 211032311179951 is an apocalyptic number.
11032311179951 is a deficient number, since it is larger than the sum of its proper divisors (1).
11032311179951 is an equidigital number, since it uses as much as digits as its factorization.
11032311179951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51030, while the sum is 44.
The spelling of 11032311179951 in words is "eleven trillion, thirty-two billion, three hundred eleven million, one hundred seventy-nine thousand, nine hundred fifty-one".
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