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11032311310981 is a prime number
BaseRepresentation
bin1010000010001010100011…
…1111110010101010000101
31110001200022202002100021221
42200202220333302222011
52421223133143422411
635244101315040341
72216025646613212
oct240425077625205
943050282070257
1011032311310981
11357386013a104
1212a21768a00b1
1362045b5c178c
142a1d76954b09
15141e9818b071
hexa08a8ff2a85

11032311310981 has 2 divisors, whose sum is σ = 11032311310982. Its totient is φ = 11032311310980.

The previous prime is 11032311310963. The next prime is 11032311311033. The reversal of 11032311310981 is 18901311323011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8651045682756 + 2381265628225 = 2941266^2 + 1543135^2 .

It is a cyclic number.

It is not a de Polignac number, because 11032311310981 - 233 = 11023721376389 is a prime.

It is a super-2 number, since 2×110323113109812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11032311310901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516155655490 + 5516155655491.

It is an arithmetic number, because the mean of its divisors is an integer number (5516155655491).

Almost surely, 211032311310981 is an apocalyptic number.

It is an amenable number.

11032311310981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11032311310981 is an equidigital number, since it uses as much as digits as its factorization.

11032311310981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 34.

Adding to 11032311310981 its reverse (18901311323011), we get a palindrome (29933622633992).

The spelling of 11032311310981 in words is "eleven trillion, thirty-two billion, three hundred eleven million, three hundred ten thousand, nine hundred eighty-one".