Base | Representation |
---|---|
bin | 110011010111111000… |
… | …1010101111010010000 |
3 | 101112202121102200101212 |
4 | 1212233301111322100 |
5 | 3301420210130000 |
6 | 122403131315252 |
7 | 10653624063266 |
oct | 1465761257220 |
9 | 345677380355 |
10 | 110323130000 |
11 | 428735924a6 |
12 | 1946ababb28 |
13 | a5324359a5 |
14 | 54a8098436 |
15 | 2d0a674c35 |
hex | 19afc55e90 |
110323130000 has 50 divisors (see below), whose sum is σ = 267103354254. Its totient is φ = 44129248000.
The previous prime is 110323129999. The next prime is 110323130003. The reversal of 110323130000 is 31323011.
It can be written as a sum of positive squares in 5 ways, for example, as 69814322176 + 40508807824 = 264224^2 + 201268^2 .
It is a tau number, because it is divible by the number of its divisors (50).
It is not an unprimeable number, because it can be changed into a prime (110323130003) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 5506157 + ... + 5526156.
Almost surely, 2110323130000 is an apocalyptic number.
110323130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
110323130000 is an abundant number, since it is smaller than the sum of its proper divisors (156780224254).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110323130000 is an equidigital number, since it uses as much as digits as its factorization.
110323130000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11032341 (or 11032320 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 110323130000 its reverse (31323011), we get a palindrome (110354453011).
The spelling of 110323130000 in words is "one hundred ten billion, three hundred twenty-three million, one hundred thirty thousand".
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