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11033030210399 is a prime number
BaseRepresentation
bin1010000010001101001111…
…0110001011001101011111
31110001202011211211012220022
42200203103312023031133
52421231121213213044
635244300515342355
72216052526300661
oct240432366131537
943052154735808
1011033030210399
113574099a1795a
1212a23375b19bb
1362054451a352
142a200420c531
15141edb3433ee
hexa08d3d8b35f

11033030210399 has 2 divisors, whose sum is σ = 11033030210400. Its totient is φ = 11033030210398.

The previous prime is 11033030210369. The next prime is 11033030210401. The reversal of 11033030210399 is 99301203033011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11033030210399 is a prime.

Together with 11033030210401, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11033030210339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516515105199 + 5516515105200.

It is an arithmetic number, because the mean of its divisors is an integer number (5516515105200).

Almost surely, 211033030210399 is an apocalyptic number.

11033030210399 is a deficient number, since it is larger than the sum of its proper divisors (1).

11033030210399 is an equidigital number, since it uses as much as digits as its factorization.

11033030210399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13122, while the sum is 35.

The spelling of 11033030210399 in words is "eleven trillion, thirty-three billion, thirty million, two hundred ten thousand, three hundred ninety-nine".