Base | Representation |
---|---|
bin | 10000000011100011001… |
… | …100000010101000111011 |
3 | 10220110212111021110001112 |
4 | 100003203030002220323 |
5 | 121034101220243342 |
6 | 2202505405310535 |
7 | 142466243365166 |
oct | 20034314025073 |
9 | 3813774243045 |
10 | 1103323212347 |
11 | 395a0a20a684 |
12 | 1599b886544b |
13 | 80073426c05 |
14 | 3b5889a6add |
15 | 1da775db682 |
hex | 100e3302a3b |
1103323212347 has 2 divisors, whose sum is σ = 1103323212348. Its totient is φ = 1103323212346.
The previous prime is 1103323212317. The next prime is 1103323212349. The reversal of 1103323212347 is 7432123233011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1103323212347 - 224 = 1103306435131 is a prime.
It is a super-2 number, since 2×11033232123472 (a number of 25 digits) contains 22 as substring.
Together with 1103323212349, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1103323212349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551661606173 + 551661606174.
It is an arithmetic number, because the mean of its divisors is an integer number (551661606174).
Almost surely, 21103323212347 is an apocalyptic number.
1103323212347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1103323212347 is an equidigital number, since it uses as much as digits as its factorization.
1103323212347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 1103323212347 its reverse (7432123233011), we get a palindrome (8535446445358).
The spelling of 1103323212347 in words is "one trillion, one hundred three billion, three hundred twenty-three million, two hundred twelve thousand, three hundred forty-seven".
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