Base | Representation |
---|---|
bin | 1010000010001110000010… |
… | …0011000011000101111101 |
3 | 1110001202201200210022011221 |
4 | 2200203200203003011331 |
5 | 2421232040241101341 |
6 | 35244334010513341 |
7 | 2216061024444052 |
oct | 240434043030575 |
9 | 43052650708157 |
10 | 11033243300221 |
11 | 357419923044a |
12 | 12a2396a35851 |
13 | 6205797086bc |
14 | 2a202463b029 |
15 | 141eeedd5ed1 |
hex | a08e08c317d |
11033243300221 has 2 divisors, whose sum is σ = 11033243300222. Its totient is φ = 11033243300220.
The previous prime is 11033243300147. The next prime is 11033243300249. The reversal of 11033243300221 is 12200334233011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10970099148996 + 63144151225 = 3312114^2 + 251285^2 .
It is a cyclic number.
It is not a de Polignac number, because 11033243300221 - 229 = 11032706429309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11033243300021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5516621650110 + 5516621650111.
It is an arithmetic number, because the mean of its divisors is an integer number (5516621650111).
Almost surely, 211033243300221 is an apocalyptic number.
It is an amenable number.
11033243300221 is a deficient number, since it is larger than the sum of its proper divisors (1).
11033243300221 is an equidigital number, since it uses as much as digits as its factorization.
11033243300221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 11033243300221 its reverse (12200334233011), we get a palindrome (23233577533232).
The spelling of 11033243300221 in words is "eleven trillion, thirty-three billion, two hundred forty-three million, three hundred thousand, two hundred twenty-one".
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