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1103332554407 is a prime number
BaseRepresentation
bin10000000011100011101…
…111101011011010100111
310220110220010212001221202
4100003203233223122213
5121034111113220112
62202510341433115
7142466415654416
oct20034357533247
93813803761852
101103332554407
11395a14510496
121599bba0b79b
1380075348165
143b589d1947d
151da783346c2
hex100e3beb6a7

1103332554407 has 2 divisors, whose sum is σ = 1103332554408. Its totient is φ = 1103332554406.

The previous prime is 1103332554391. The next prime is 1103332554419. The reversal of 1103332554407 is 7044552333011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1103332554407 - 24 = 1103332554391 is a prime.

It is a super-2 number, since 2×11033325544072 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1103332554427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551666277203 + 551666277204.

It is an arithmetic number, because the mean of its divisors is an integer number (551666277204).

Almost surely, 21103332554407 is an apocalyptic number.

1103332554407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1103332554407 is an equidigital number, since it uses as much as digits as its factorization.

1103332554407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 38.

Adding to 1103332554407 its reverse (7044552333011), we get a palindrome (8147884887418).

The spelling of 1103332554407 in words is "one trillion, one hundred three billion, three hundred thirty-two million, five hundred fifty-four thousand, four hundred seven".