Base | Representation |
---|---|
bin | 10000000011100011110… |
… | …101101000000010100111 |
3 | 10220110220020210021112222 |
4 | 100003203311220002213 |
5 | 121034112013112242 |
6 | 2202510435102555 |
7 | 142466435136626 |
oct | 20034365500247 |
9 | 3813806707488 |
10 | 1103334113447 |
11 | 395a15385855 |
12 | 159a00441a5b |
13 | 80075772977 |
14 | 3b58a2036bd |
15 | 1da785415d2 |
hex | 100e3d680a7 |
1103334113447 has 2 divisors, whose sum is σ = 1103334113448. Its totient is φ = 1103334113446.
The previous prime is 1103334113381. The next prime is 1103334113449. The reversal of 1103334113447 is 7443114333011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1103334113447 - 28 = 1103334113191 is a prime.
Together with 1103334113449, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1103334113449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551667056723 + 551667056724.
It is an arithmetic number, because the mean of its divisors is an integer number (551667056724).
Almost surely, 21103334113447 is an apocalyptic number.
1103334113447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1103334113447 is an equidigital number, since it uses as much as digits as its factorization.
1103334113447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36288, while the sum is 35.
Adding to 1103334113447 its reverse (7443114333011), we get a palindrome (8546448446458).
The spelling of 1103334113447 in words is "one trillion, one hundred three billion, three hundred thirty-four million, one hundred thirteen thousand, four hundred forty-seven".
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