Base | Representation |
---|---|
bin | 10000000011100100110… |
… | …111000011010011010111 |
3 | 10220110221110001122100002 |
4 | 100003210313003103113 |
5 | 121034130410430341 |
6 | 2202512250441515 |
7 | 142500034001621 |
oct | 20034467032327 |
9 | 3813843048302 |
10 | 1103351264471 |
11 | 395a2402a655 |
12 | 159a0613329b |
13 | 800791993c1 |
14 | 3b58c5c9c11 |
15 | 1da79ccd29b |
hex | 100e4dc34d7 |
1103351264471 has 2 divisors, whose sum is σ = 1103351264472. Its totient is φ = 1103351264470.
The previous prime is 1103351264453. The next prime is 1103351264479. The reversal of 1103351264471 is 1744621533011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1103351264471 - 210 = 1103351263447 is a prime.
It is a super-3 number, since 3×11033512644713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1103351264479) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551675632235 + 551675632236.
It is an arithmetic number, because the mean of its divisors is an integer number (551675632236).
Almost surely, 21103351264471 is an apocalyptic number.
1103351264471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1103351264471 is an equidigital number, since it uses as much as digits as its factorization.
1103351264471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 38.
Adding to 1103351264471 its reverse (1744621533011), we get a palindrome (2847972797482).
The spelling of 1103351264471 in words is "one trillion, one hundred three billion, three hundred fifty-one million, two hundred sixty-four thousand, four hundred seventy-one".
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