Base | Representation |
---|---|
bin | 10100100011010110… |
… | …10111101100001111 |
3 | 1001110222102021122222 |
4 | 22101223113230033 |
5 | 140044201001033 |
6 | 5022520525555 |
7 | 540301311425 |
oct | 122153275417 |
9 | 31428367588 |
10 | 11034000143 |
11 | 4752450691 |
12 | 217b3208bb |
13 | 106aca028a |
14 | 769601115 |
15 | 448a58598 |
hex | 291ad7b0f |
11034000143 has 2 divisors, whose sum is σ = 11034000144. Its totient is φ = 11034000142.
The previous prime is 11034000137. The next prime is 11034000149. The reversal of 11034000143 is 34100043011.
It is a balanced prime because it is at equal distance from previous prime (11034000137) and next prime (11034000149).
It is a cyclic number.
It is not a de Polignac number, because 11034000143 - 214 = 11033983759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11034000149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5517000071 + 5517000072.
It is an arithmetic number, because the mean of its divisors is an integer number (5517000072).
Almost surely, 211034000143 is an apocalyptic number.
11034000143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11034000143 is an equidigital number, since it uses as much as digits as its factorization.
11034000143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 11034000143 its reverse (34100043011), we get a palindrome (45134043154).
The spelling of 11034000143 in words is "eleven billion, thirty-four million, one hundred forty-three", and thus it is an aban number.
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