Base | Representation |
---|---|
bin | 10000000011101000011… |
… | …000110101000011100111 |
3 | 10220111002120102121112021 |
4 | 100003220120311003213 |
5 | 121034241033410123 |
6 | 2202522203204011 |
7 | 142501353036253 |
oct | 20035030650347 |
9 | 3814076377467 |
10 | 1103410450663 |
11 | 395a54485064 |
12 | 159a21b16607 |
13 | 8008851cb11 |
14 | 3b5963d5263 |
15 | 1da800bec5d |
hex | 100e86350e7 |
1103410450663 has 2 divisors, whose sum is σ = 1103410450664. Its totient is φ = 1103410450662.
The previous prime is 1103410450631. The next prime is 1103410450691. The reversal of 1103410450663 is 3660540143011.
It is a strong prime.
It is an emirp because it is prime and its reverse (3660540143011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1103410450663 - 25 = 1103410450631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1103410450463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 551705225331 + 551705225332.
It is an arithmetic number, because the mean of its divisors is an integer number (551705225332).
Almost surely, 21103410450663 is an apocalyptic number.
1103410450663 is a deficient number, since it is larger than the sum of its proper divisors (1).
1103410450663 is an equidigital number, since it uses as much as digits as its factorization.
1103410450663 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 1103410450663 its reverse (3660540143011), we get a palindrome (4763950593674).
The spelling of 1103410450663 in words is "one trillion, one hundred three billion, four hundred ten million, four hundred fifty thousand, six hundred sixty-three".
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