1103413000130 has 64 divisors (see below), whose sum is σ = 2329588200960. Its totient is φ = 368465570304.

The previous prime is 1103413000099. The next prime is 1103413000133. The reversal of 1103413000130 is 310003143011.

It is a junction number, because it is equal to n+sod(n) for n = 1103413000099 and 1103413000108.

It is not an unprimeable number, because it can be changed into a prime (1103413000133) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 577190 + ... + 1593729.

It is an arithmetic number, because the mean of its divisors is an integer number (36399815640).

Almost surely, 2^{1103413000130} is an apocalyptic number.

1103413000130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1103413000130 is an abundant number, since it is smaller than the sum of its proper divisors (1226175200830).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1103413000130 is a wasteful number, since it uses less digits than its factorization.

1103413000130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2171123.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1103413000130 its reverse (310003143011), we get a palindrome (1413416143141).

The spelling of 1103413000130 in words is "one trillion, one hundred three billion, four hundred thirteen million, one hundred thirty", and thus it is an aban number.