Base | Representation |
---|---|
bin | 10100100100000110… |
… | …01001111101000101 |
3 | 1001111102011001201221 |
4 | 22102003021331011 |
5 | 140102300012313 |
6 | 5023302320341 |
7 | 540405311011 |
oct | 122203117505 |
9 | 31442131657 |
10 | 11040235333 |
11 | 4755a1a236 |
12 | 21814290b1 |
13 | 106c37433a |
14 | 76a385541 |
15 | 44938ac8d |
hex | 2920c9f45 |
11040235333 has 2 divisors, whose sum is σ = 11040235334. Its totient is φ = 11040235332.
The previous prime is 11040235321. The next prime is 11040235351. The reversal of 11040235333 is 33353204011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6874565569 + 4165669764 = 82913^2 + 64542^2 .
It is an emirp because it is prime and its reverse (33353204011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11040235333 - 225 = 11006680901 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11040235298 and 11040235307.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11040235733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520117666 + 5520117667.
It is an arithmetic number, because the mean of its divisors is an integer number (5520117667).
Almost surely, 211040235333 is an apocalyptic number.
It is an amenable number.
11040235333 is a deficient number, since it is larger than the sum of its proper divisors (1).
11040235333 is an equidigital number, since it uses as much as digits as its factorization.
11040235333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 11040235333 its reverse (33353204011), we get a palindrome (44393439344).
The spelling of 11040235333 in words is "eleven billion, forty million, two hundred thirty-five thousand, three hundred thirty-three".
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