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1104024441407 is a prime number
BaseRepresentation
bin10000000100001100111…
…111000001001000111111
310220112200100202120111012
4100010030333001020333
5121042020224111112
62203103135145435
7142522516625606
oct20041477011077
93815610676435
101104024441407
1139623a019428
12159b7367527b
13801557a6854
143b613b80a3d
151dab8e53022
hex1010cfc123f

1104024441407 has 2 divisors, whose sum is σ = 1104024441408. Its totient is φ = 1104024441406.

The previous prime is 1104024441397. The next prime is 1104024441413. The reversal of 1104024441407 is 7041444204011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1104024441407 - 26 = 1104024441343 is a prime.

It is a super-2 number, since 2×11040244414072 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1104024441427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552012220703 + 552012220704.

It is an arithmetic number, because the mean of its divisors is an integer number (552012220704).

Almost surely, 21104024441407 is an apocalyptic number.

1104024441407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104024441407 is an equidigital number, since it uses as much as digits as its factorization.

1104024441407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14336, while the sum is 32.

Adding to 1104024441407 its reverse (7041444204011), we get a palindrome (8145468645418).

The spelling of 1104024441407 in words is "one trillion, one hundred four billion, twenty-four million, four hundred forty-one thousand, four hundred seven".