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11041113157 is a prime number
BaseRepresentation
bin10100100100001101…
…00000010001000101
31001111110210122212221
422102012200101011
5140103011110112
65023333212341
7540415625164
oct122206402105
931443718787
1011041113157
114756469808
1221817910b1
13106c5c0a69
1476a5333db
154494b0e07
hex2921a0445

11041113157 has 2 divisors, whose sum is σ = 11041113158. Its totient is φ = 11041113156.

The previous prime is 11041113151. The next prime is 11041113221. The reversal of 11041113157 is 75131114011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10866186081 + 174927076 = 104241^2 + 13226^2 .

It is an emirp because it is prime and its reverse (75131114011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11041113157 - 227 = 10906895429 is a prime.

It is a super-4 number, since 4×110411131574 (a number of 41 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11041113151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520556578 + 5520556579.

It is an arithmetic number, because the mean of its divisors is an integer number (5520556579).

Almost surely, 211041113157 is an apocalyptic number.

It is an amenable number.

11041113157 is a deficient number, since it is larger than the sum of its proper divisors (1).

11041113157 is an equidigital number, since it uses as much as digits as its factorization.

11041113157 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 420, while the sum is 25.

Adding to 11041113157 its reverse (75131114011), we get a palindrome (86172227168).

The spelling of 11041113157 in words is "eleven billion, forty-one million, one hundred thirteen thousand, one hundred fifty-seven".