Base | Representation |
---|---|
bin | 110011011010100010… |
… | …1101010111010110101 |
3 | 101112222211022021101121 |
4 | 1212311011222322311 |
5 | 3302111030020023 |
6 | 122420035423541 |
7 | 10656056306335 |
oct | 1466505527265 |
9 | 345884267347 |
10 | 110412345013 |
11 | 42909988013 |
12 | 19494a54bb1 |
13 | a547a71539 |
14 | 54b5c7d0c5 |
15 | 2d133e8d5d |
hex | 19b516aeb5 |
110412345013 has 2 divisors, whose sum is σ = 110412345014. Its totient is φ = 110412345012.
The previous prime is 110412344981. The next prime is 110412345053. The reversal of 110412345013 is 310543214011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 81132686244 + 29279658769 = 284838^2 + 171113^2 .
It is a cyclic number.
It is not a de Polignac number, because 110412345013 - 25 = 110412344981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110412345053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55206172506 + 55206172507.
It is an arithmetic number, because the mean of its divisors is an integer number (55206172507).
Almost surely, 2110412345013 is an apocalyptic number.
It is an amenable number.
110412345013 is a deficient number, since it is larger than the sum of its proper divisors (1).
110412345013 is an equidigital number, since it uses as much as digits as its factorization.
110412345013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 110412345013 its reverse (310543214011), we get a palindrome (420955559024).
The spelling of 110412345013 in words is "one hundred ten billion, four hundred twelve million, three hundred forty-five thousand, thirteen".
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