Base | Representation |
---|---|
bin | 10100100100001110… |
… | …11011000110011101 |
3 | 1001111111020220110021 |
4 | 22102013123012131 |
5 | 140103041313031 |
6 | 5023342312141 |
7 | 540420650566 |
oct | 122207330635 |
9 | 31444226407 |
10 | 11041354141 |
11 | 4756613874 |
12 | 2181888651 |
13 | 106c67665c |
14 | 76a59716d |
15 | 44950c511 |
hex | 2921db19d |
11041354141 has 2 divisors, whose sum is σ = 11041354142. Its totient is φ = 11041354140.
The previous prime is 11041354117. The next prime is 11041354169. The reversal of 11041354141 is 14145314011.
11041354141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6467537241 + 4573816900 = 80421^2 + 67630^2 .
It is a cyclic number.
It is not a de Polignac number, because 11041354141 - 211 = 11041352093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11041354241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520677070 + 5520677071.
It is an arithmetic number, because the mean of its divisors is an integer number (5520677071).
Almost surely, 211041354141 is an apocalyptic number.
It is an amenable number.
11041354141 is a deficient number, since it is larger than the sum of its proper divisors (1).
11041354141 is an equidigital number, since it uses as much as digits as its factorization.
11041354141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 11041354141 its reverse (14145314011), we get a palindrome (25186668152).
The spelling of 11041354141 in words is "eleven billion, forty-one million, three hundred fifty-four thousand, one hundred forty-one".
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