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110426957 is a prime number
BaseRepresentation
bin1101001010011…
…11101101001101
321200210021022022
412211033231031
5211232130312
614542455525
72510420324
oct645175515
9250707268
10110426957
1157373453
1230b945a5
1319b547c4
14109470bb
159a64172
hex694fb4d

110426957 has 2 divisors, whose sum is σ = 110426958. Its totient is φ = 110426956.

The previous prime is 110426947. The next prime is 110426959. The reversal of 110426957 is 759624011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85636516 + 24790441 = 9254^2 + 4979^2 .

It is a cyclic number.

It is not a de Polignac number, because 110426957 - 210 = 110425933 is a prime.

It is a super-2 number, since 2×1104269572 = 24388225664559698, which contains 22 as substring.

Together with 110426959, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110426959) by changing a digit.

It is a good prime.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55213478 + 55213479.

It is an arithmetic number, because the mean of its divisors is an integer number (55213479).

Almost surely, 2110426957 is an apocalyptic number.

It is an amenable number.

110426957 is a deficient number, since it is larger than the sum of its proper divisors (1).

110426957 is an equidigital number, since it uses as much as digits as its factorization.

110426957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 35.

The square root of 110426957 is about 10508.4231452678. The cubic root of 110426957 is about 479.7611036324.

The spelling of 110426957 in words is "one hundred ten million, four hundred twenty-six thousand, nine hundred fifty-seven".