Base | Representation |
---|---|
bin | 10100100100011110… |
… | …00000010010001101 |
3 | 1001111121222212112102 |
4 | 22102033000102031 |
5 | 140104043411303 |
6 | 5023453044445 |
7 | 540443565524 |
oct | 122217002215 |
9 | 31447885472 |
10 | 11043341453 |
11 | 4757750981 |
12 | 2182486725 |
13 | 106cbc1091 |
14 | 76a9534bb |
15 | 4497a1288 |
hex | 2923c048d |
11043341453 has 2 divisors, whose sum is σ = 11043341454. Its totient is φ = 11043341452.
The previous prime is 11043341437. The next prime is 11043341467. The reversal of 11043341453 is 35414334011.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8944052329 + 2099289124 = 94573^2 + 45818^2 .
It is a cyclic number.
It is not a de Polignac number, because 11043341453 - 24 = 11043341437 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11043341473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521670726 + 5521670727.
It is an arithmetic number, because the mean of its divisors is an integer number (5521670727).
Almost surely, 211043341453 is an apocalyptic number.
It is an amenable number.
11043341453 is a deficient number, since it is larger than the sum of its proper divisors (1).
11043341453 is an equidigital number, since it uses as much as digits as its factorization.
11043341453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 11043341453 its reverse (35414334011), we get a palindrome (46457675464).
The spelling of 11043341453 in words is "eleven billion, forty-three million, three hundred forty-one thousand, four hundred fifty-three".
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