Base | Representation |
---|---|
bin | 1010000010110100010010… |
… | …1000100100100100000111 |
3 | 1110002202020100220211121111 |
4 | 2200231010220210210013 |
5 | 2421414103133413411 |
6 | 35253153005225451 |
7 | 2216603350415566 |
oct | 240550450444407 |
9 | 43082210824544 |
10 | 11043512404231 |
11 | 357858893726a |
12 | 12a4381b62287 |
13 | 621525096bc8 |
14 | 2a271a40dbdd |
15 | 1424016ed721 |
hex | a0b44a24907 |
11043512404231 has 2 divisors, whose sum is σ = 11043512404232. Its totient is φ = 11043512404230.
The previous prime is 11043512404219. The next prime is 11043512404279. The reversal of 11043512404231 is 13240421534011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11043512404231 - 221 = 11043510307079 is a prime.
It is a super-2 number, since 2×110435124042312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11043512404193 and 11043512404202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11043512408231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521756202115 + 5521756202116.
It is an arithmetic number, because the mean of its divisors is an integer number (5521756202116).
Almost surely, 211043512404231 is an apocalyptic number.
11043512404231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11043512404231 is an equidigital number, since it uses as much as digits as its factorization.
11043512404231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 11043512404231 its reverse (13240421534011), we get a palindrome (24283933938242).
The spelling of 11043512404231 in words is "eleven trillion, forty-three billion, five hundred twelve million, four hundred four thousand, two hundred thirty-one".
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