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11043512404231 is a prime number
BaseRepresentation
bin1010000010110100010010…
…1000100100100100000111
31110002202020100220211121111
42200231010220210210013
52421414103133413411
635253153005225451
72216603350415566
oct240550450444407
943082210824544
1011043512404231
11357858893726a
1212a4381b62287
13621525096bc8
142a271a40dbdd
151424016ed721
hexa0b44a24907

11043512404231 has 2 divisors, whose sum is σ = 11043512404232. Its totient is φ = 11043512404230.

The previous prime is 11043512404219. The next prime is 11043512404279. The reversal of 11043512404231 is 13240421534011.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11043512404231 - 221 = 11043510307079 is a prime.

It is a super-2 number, since 2×110435124042312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11043512404193 and 11043512404202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11043512408231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5521756202115 + 5521756202116.

It is an arithmetic number, because the mean of its divisors is an integer number (5521756202116).

Almost surely, 211043512404231 is an apocalyptic number.

11043512404231 is a deficient number, since it is larger than the sum of its proper divisors (1).

11043512404231 is an equidigital number, since it uses as much as digits as its factorization.

11043512404231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 11043512404231 its reverse (13240421534011), we get a palindrome (24283933938242).

The spelling of 11043512404231 in words is "eleven trillion, forty-three billion, five hundred twelve million, four hundred four thousand, two hundred thirty-one".