Base | Representation |
---|---|
bin | 11001000111001000010100… |
… | …011101000001010110100111 |
3 | 112111001001212101121110220221 |
4 | 121013020110131001112213 |
5 | 103433431414320421013 |
6 | 1030515542233505211 |
7 | 32156052132412204 |
oct | 3107102435012647 |
9 | 474031771543827 |
10 | 110441132201383 |
11 | 3220a903a2a255 |
12 | 10478293872207 |
13 | 49817284089a9 |
14 | 1d3b544bd2cab |
15 | cb7c621da08d |
hex | 6472147415a7 |
110441132201383 has 2 divisors, whose sum is σ = 110441132201384. Its totient is φ = 110441132201382.
The previous prime is 110441132201359. The next prime is 110441132201419. The reversal of 110441132201383 is 383102231144011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110441132201383 - 29 = 110441132200871 is a prime.
It is a super-2 number, since 2×1104411322013832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110441132201483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55220566100691 + 55220566100692.
It is an arithmetic number, because the mean of its divisors is an integer number (55220566100692).
Almost surely, 2110441132201383 is an apocalyptic number.
110441132201383 is a deficient number, since it is larger than the sum of its proper divisors (1).
110441132201383 is an equidigital number, since it uses as much as digits as its factorization.
110441132201383 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 34.
Adding to 110441132201383 its reverse (383102231144011), we get a palindrome (493543363345394).
The spelling of 110441132201383 in words is "one hundred ten trillion, four hundred forty-one billion, one hundred thirty-two million, two hundred one thousand, three hundred eighty-three".
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