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11045040530213 is a prime number
BaseRepresentation
bin1010000010111001111110…
…1101111010001100100101
31110002220011212100200101002
42200232133231322030211
52421430220333431323
635254004354243045
72216656254315434
oct240563755721445
943086155320332
1011045040530213
1135791a24879a8
1212a4729886485
13621709856171
142a282335511b
15142490951828
hexa0b9fb7a325

11045040530213 has 2 divisors, whose sum is σ = 11045040530214. Its totient is φ = 11045040530212.

The previous prime is 11045040530207. The next prime is 11045040530219. The reversal of 11045040530213 is 31203504054011.

It is a balanced prime because it is at equal distance from previous prime (11045040530207) and next prime (11045040530219).

It can be written as a sum of positive squares in only one way, i.e., 8803812962884 + 2241227567329 = 2967122^2 + 1497073^2 .

It is a cyclic number.

It is not a de Polignac number, because 11045040530213 - 230 = 11043966788389 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11045040530219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522520265106 + 5522520265107.

It is an arithmetic number, because the mean of its divisors is an integer number (5522520265107).

Almost surely, 211045040530213 is an apocalyptic number.

It is an amenable number.

11045040530213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11045040530213 is an equidigital number, since it uses as much as digits as its factorization.

11045040530213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 11045040530213 its reverse (31203504054011), we get a palindrome (42248544584224).

The spelling of 11045040530213 in words is "eleven trillion, forty-five billion, forty million, five hundred thirty thousand, two hundred thirteen".