Base | Representation |
---|---|
bin | 1010000010111010101000… |
… | …0000010011100110110011 |
3 | 1110002220121220010101222012 |
4 | 2200232222000103212303 |
5 | 2421431044030000133 |
6 | 35254033441433135 |
7 | 2216663451332366 |
oct | 240565200234663 |
9 | 43086556111865 |
10 | 11045213125043 |
11 | 3579280951a59 |
12 | 12a477763b7ab |
13 | 621736536596 |
14 | 2a283c2420dd |
15 | 1424a0b95b48 |
hex | a0baa0139b3 |
11045213125043 has 2 divisors, whose sum is σ = 11045213125044. Its totient is φ = 11045213125042.
The previous prime is 11045213125033. The next prime is 11045213125117. The reversal of 11045213125043 is 34052131254011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11045213125043 - 24 = 11045213125027 is a prime.
It is not a weakly prime, because it can be changed into another prime (11045213125033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522606562521 + 5522606562522.
It is an arithmetic number, because the mean of its divisors is an integer number (5522606562522).
Almost surely, 211045213125043 is an apocalyptic number.
11045213125043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11045213125043 is an equidigital number, since it uses as much as digits as its factorization.
11045213125043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 11045213125043 its reverse (34052131254011), we get a palindrome (45097344379054).
The spelling of 11045213125043 in words is "eleven trillion, forty-five billion, two hundred thirteen million, one hundred twenty-five thousand, forty-three".
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