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11045213125117 is a prime number
BaseRepresentation
bin1010000010111010101000…
…0000010011100111111101
31110002220121220010102001221
42200232222000103213331
52421431044030000432
635254033441433341
72216663451332533
oct240565200234775
943086556112057
1011045213125117
113579280952016
1212a477763b851
13621736536622
142a283c242153
151424a0b95b97
hexa0baa0139fd

11045213125117 has 2 divisors, whose sum is σ = 11045213125118. Its totient is φ = 11045213125116.

The previous prime is 11045213125043. The next prime is 11045213125171. The reversal of 11045213125117 is 71152131254011.

Together with next prime (11045213125171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10292585738436 + 752627386681 = 3208206^2 + 867541^2 .

It is a cyclic number.

It is not a de Polignac number, because 11045213125117 - 235 = 11010853386749 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11045213125187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522606562558 + 5522606562559.

It is an arithmetic number, because the mean of its divisors is an integer number (5522606562559).

Almost surely, 211045213125117 is an apocalyptic number.

It is an amenable number.

11045213125117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11045213125117 is an equidigital number, since it uses as much as digits as its factorization.

11045213125117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8400, while the sum is 34.

Adding to 11045213125117 its reverse (71152131254011), we get a palindrome (82197344379128).

The spelling of 11045213125117 in words is "eleven trillion, forty-five billion, two hundred thirteen million, one hundred twenty-five thousand, one hundred seventeen".