Base | Representation |
---|---|
bin | 1010000010111010101000… |
… | …0000010011101000000110 |
3 | 1110002220121220010102002021 |
4 | 2200232222000103220012 |
5 | 2421431044030001001 |
6 | 35254033441433354 |
7 | 2216663451332545 |
oct | 240565200235006 |
9 | 43086556112067 |
10 | 11045213125126 |
11 | 3579280952024 |
12 | 12a477763b85a |
13 | 62173653662b |
14 | 2a283c24215c |
15 | 1424a0b95ba1 |
hex | a0baa013a06 |
11045213125126 has 4 divisors (see below), whose sum is σ = 16567819687692. Its totient is φ = 5522606562562.
The previous prime is 11045213125117. The next prime is 11045213125171. The reversal of 11045213125126 is 62152131254011.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×110452131251263 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11045213125091 and 11045213125100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2761303281280 + ... + 2761303281283.
It is an arithmetic number, because the mean of its divisors is an integer number (4141954921923).
Almost surely, 211045213125126 is an apocalyptic number.
11045213125126 is a deficient number, since it is larger than the sum of its proper divisors (5522606562566).
11045213125126 is an equidigital number, since it uses as much as digits as its factorization.
11045213125126 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5522606562565.
The product of its (nonzero) digits is 14400, while the sum is 34.
Adding to 11045213125126 its reverse (62152131254011), we get a palindrome (73197344379137).
The spelling of 11045213125126 in words is "eleven trillion, forty-five billion, two hundred thirteen million, one hundred twenty-five thousand, one hundred twenty-six".
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