11048114711 has 2 divisors, whose sum is σ = 11048114712. Its totient is φ = 11048114710.

The previous prime is 11048114681. The next prime is 11048114713. The reversal of 11048114711 is 11741184011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11048114711 is a prime.

It is a super-2 number, since 2×11048114711² (a number of 21 digits) contains 22 as substring.

Together with 11048114713, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11048114713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5524057355 + 5524057356.

It is an arithmetic number, because the mean of its divisors is an integer number (5524057356).

Almost surely, 2^11048114711 is an apocalyptic number.

11048114711 is a deficient number, since it is larger than the sum of its proper divisors (1).

11048114711 is an equidigital number, since it uses as much as digits as its factorization.

11048114711 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 896, while the sum is 29.

Adding to 11048114711 its reverse (11741184011), we get a palindrome (22789298722).

The spelling of 11048114711 in words is "eleven billion, forty-eight million, one hundred fourteen thousand, seven hundred eleven".