1104935066413 has 2 divisors, whose sum is σ = 1104935066414. Its totient is φ = 1104935066412.

The previous prime is 1104935066407. The next prime is 1104935066419. The reversal of 1104935066413 is 3146605394011.

It is a balanced prime because it is at equal distance from previous prime (1104935066407) and next prime (1104935066419).

It can be written as a sum of positive squares in only one way, i.e., 1101498527529 + 3436538884 = 1049523^2 + 58622^2 .

It is an emirp because it is prime and its reverse (3146605394011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1104935066413 is a prime.

It is a super-3 number, since 3×1104935066413³ (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1104935066413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1104935066419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552467533206 + 552467533207.

It is an arithmetic number, because the mean of its divisors is an integer number (552467533207).

Almost surely, 2^{1104935066413} is an apocalyptic number.

It is an amenable number.

1104935066413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104935066413 is an equidigital number, since it uses as much as digits as its factorization.

1104935066413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 233280, while the sum is 43.

The spelling of 1104935066413 in words is "one trillion, one hundred four billion, nine hundred thirty-five million, sixty-six thousand, four hundred thirteen".