Base | Representation |
---|---|
bin | 10000000101000111001… |
… | …000100001001100110111 |
3 | 10220122012100110121202201 |
4 | 100011013020201030313 |
5 | 121101020000314201 |
6 | 2203344025045331 |
7 | 142555634054533 |
oct | 20050710411467 |
9 | 3818170417681 |
10 | 1105000010551 |
11 | 39669a775a18 |
12 | 15a1a6326847 |
13 | 8027c93b8b8 |
14 | 3b6a756cbc3 |
15 | 1db2490a801 |
hex | 10147221337 |
1105000010551 has 2 divisors, whose sum is σ = 1105000010552. Its totient is φ = 1105000010550.
The previous prime is 1105000010507. The next prime is 1105000010593. The reversal of 1105000010551 is 1550100005011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1105000010551 - 219 = 1104999486263 is a prime.
It is a super-2 number, since 2×11050000105512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1105000080551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552500005275 + 552500005276.
It is an arithmetic number, because the mean of its divisors is an integer number (552500005276).
Almost surely, 21105000010551 is an apocalyptic number.
1105000010551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1105000010551 is an equidigital number, since it uses as much as digits as its factorization.
1105000010551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 125, while the sum is 19.
Adding to 1105000010551 its reverse (1550100005011), we get a palindrome (2655100015562).
The spelling of 1105000010551 in words is "one trillion, one hundred five billion, ten thousand, five hundred fifty-one".
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