11050283983 has 2 divisors, whose sum is σ = 11050283984. Its totient is φ = 11050283982.

The previous prime is 11050283977. The next prime is 11050284023. The reversal of 11050283983 is 38938205011.

It is an a-pointer prime, because the next prime (11050284023) can be obtained adding 11050283983 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11050283983 - 2⁹ = 11050283471 is a prime.

It is a super-2 number, since 2×11050283983² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11050583983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525141991 + 5525141992.

It is an arithmetic number, because the mean of its divisors is an integer number (5525141992).

Almost surely, 2^11050283983 is an apocalyptic number.

11050283983 is a deficient number, since it is larger than the sum of its proper divisors (1).

11050283983 is an equidigital number, since it uses as much as digits as its factorization.

11050283983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 40.

Adding to 11050283983 its reverse (38938205011), we get a palindrome (49988488994).

It can be divided in two parts, 1105028 and 3983, that added together give a palindrome (1109011).

The spelling of 11050283983 in words is "eleven billion, fifty million, two hundred eighty-three thousand, nine hundred eighty-three".