Base | Representation |
---|---|
bin | 10100100101010011… |
… | …10000110110000111 |
3 | 1001112010012020211021 |
4 | 22102221300312013 |
5 | 140112342343403 |
6 | 5024303252011 |
7 | 540560322433 |
oct | 122251606607 |
9 | 31463166737 |
10 | 11050356103 |
11 | 4760702106 |
12 | 21848aa007 |
13 | 10714a8b67 |
14 | 76b85b9c3 |
15 | 44a1d98bd |
hex | 292a70d87 |
11050356103 has 2 divisors, whose sum is σ = 11050356104. Its totient is φ = 11050356102.
The previous prime is 11050356067. The next prime is 11050356113. The reversal of 11050356103 is 30165305011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11050356103 - 213 = 11050347911 is a prime.
It is a super-2 number, since 2×110503561032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11050356113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525178051 + 5525178052.
It is an arithmetic number, because the mean of its divisors is an integer number (5525178052).
Almost surely, 211050356103 is an apocalyptic number.
11050356103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11050356103 is an equidigital number, since it uses as much as digits as its factorization.
11050356103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 25.
The spelling of 11050356103 in words is "eleven billion, fifty million, three hundred fifty-six thousand, one hundred three".
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