Base | Representation |
---|---|
bin | 10100100101010101… |
… | …00001011001111011 |
3 | 1001112010120100122221 |
4 | 22102222201121323 |
5 | 140112420230003 |
6 | 5024311424511 |
7 | 540562111345 |
oct | 122252413173 |
9 | 31463510587 |
10 | 11050555003 |
11 | 4760828594 |
12 | 2184985137 |
13 | 1071548557 |
14 | 76b8b0295 |
15 | 44a2287bd |
hex | 292aa167b |
11050555003 has 2 divisors, whose sum is σ = 11050555004. Its totient is φ = 11050555002.
The previous prime is 11050555001. The next prime is 11050555007. The reversal of 11050555003 is 30055505011.
11050555003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11050555003 - 21 = 11050555001 is a prime.
It is a super-2 number, since 2×110505550032 (a number of 21 digits) contains 22 as substring.
Together with 11050555001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11050555001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525277501 + 5525277502.
It is an arithmetic number, because the mean of its divisors is an integer number (5525277502).
Almost surely, 211050555003 is an apocalyptic number.
11050555003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11050555003 is an equidigital number, since it uses as much as digits as its factorization.
11050555003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1875, while the sum is 25.
The spelling of 11050555003 in words is "eleven billion, fifty million, five hundred fifty-five thousand, three".
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