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11050555003 is a prime number
BaseRepresentation
bin10100100101010101…
…00001011001111011
31001112010120100122221
422102222201121323
5140112420230003
65024311424511
7540562111345
oct122252413173
931463510587
1011050555003
114760828594
122184985137
131071548557
1476b8b0295
1544a2287bd
hex292aa167b

11050555003 has 2 divisors, whose sum is σ = 11050555004. Its totient is φ = 11050555002.

The previous prime is 11050555001. The next prime is 11050555007. The reversal of 11050555003 is 30055505011.

11050555003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11050555003 - 21 = 11050555001 is a prime.

It is a super-2 number, since 2×110505550032 (a number of 21 digits) contains 22 as substring.

Together with 11050555001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11050555001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5525277501 + 5525277502.

It is an arithmetic number, because the mean of its divisors is an integer number (5525277502).

Almost surely, 211050555003 is an apocalyptic number.

11050555003 is a deficient number, since it is larger than the sum of its proper divisors (1).

11050555003 is an equidigital number, since it uses as much as digits as its factorization.

11050555003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1875, while the sum is 25.

The spelling of 11050555003 in words is "eleven billion, fifty million, five hundred fifty-five thousand, three".