Base | Representation |
---|---|
bin | 1010000011011101110100… |
… | …0111010000100001011111 |
3 | 1110010211000022001210112021 |
4 | 2200313131013100201133 |
5 | 2422104421043120111 |
6 | 35302235124121011 |
7 | 2220446536013122 |
oct | 240673507204137 |
9 | 43124008053467 |
10 | 11054660520031 |
11 | 358228973a707 |
12 | 12a6573536167 |
13 | 6225b08b092b |
14 | 2a3096c383b9 |
15 | 142855298d71 |
hex | a0ddd1d085f |
11054660520031 has 2 divisors, whose sum is σ = 11054660520032. Its totient is φ = 11054660520030.
The previous prime is 11054660520017. The next prime is 11054660520073. The reversal of 11054660520031 is 13002506645011.
11054660520031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11054660520031 - 223 = 11054652131423 is a prime.
It is a super-2 number, since 2×110546605200312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11054660520331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5527330260015 + 5527330260016.
It is an arithmetic number, because the mean of its divisors is an integer number (5527330260016).
Almost surely, 211054660520031 is an apocalyptic number.
11054660520031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11054660520031 is an equidigital number, since it uses as much as digits as its factorization.
11054660520031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 34.
The spelling of 11054660520031 in words is "eleven trillion, fifty-four billion, six hundred sixty million, five hundred twenty thousand, thirty-one".
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