Base | Representation |
---|---|
bin | 10100101010101100… |
… | …00001100001011101 |
3 | 1001122021011110200122 |
4 | 22111112001201131 |
5 | 140210422410211 |
6 | 5032555204325 |
7 | 541646206634 |
oct | 122526014135 |
9 | 31567143618 |
10 | 11095513181 |
11 | 4784145305 |
12 | 2197a466a5 |
13 | 107a959b1c |
14 | 77385451b |
15 | 44e1596db |
hex | 29558185d |
11095513181 has 2 divisors, whose sum is σ = 11095513182. Its totient is φ = 11095513180.
The previous prime is 11095513159. The next prime is 11095513183. The reversal of 11095513181 is 18131559011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9699295225 + 1396217956 = 98485^2 + 37366^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11095513181 is a prime.
It is a super-2 number, since 2×110955131812 (a number of 21 digits) contains 22 as substring.
Together with 11095513183, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11095513183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5547756590 + 5547756591.
It is an arithmetic number, because the mean of its divisors is an integer number (5547756591).
Almost surely, 211095513181 is an apocalyptic number.
It is an amenable number.
11095513181 is a deficient number, since it is larger than the sum of its proper divisors (1).
11095513181 is an equidigital number, since it uses as much as digits as its factorization.
11095513181 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 35.
The spelling of 11095513181 in words is "eleven billion, ninety-five million, five hundred thirteen thousand, one hundred eighty-one".
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