Base | Representation |
---|---|
bin | 10100101011001110… |
… | …00001100110010101 |
3 | 1001122120112220012211 |
4 | 22111213001212111 |
5 | 140213043014231 |
6 | 5033234513421 |
7 | 542032121254 |
oct | 122547014625 |
9 | 31576486184 |
10 | 11099969941 |
11 | 4786709785 |
12 | 2199435871 |
13 | 107b85a568 |
14 | 77429479b |
15 | 44e739eb1 |
hex | 2959c1995 |
11099969941 has 2 divisors, whose sum is σ = 11099969942. Its totient is φ = 11099969940.
The previous prime is 11099969939. The next prime is 11099969977. The reversal of 11099969941 is 14996999011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10278918225 + 821051716 = 101385^2 + 28654^2 .
It is a cyclic number.
It is not a de Polignac number, because 11099969941 - 21 = 11099969939 is a prime.
It is a super-2 number, since 2×110999699412 (a number of 21 digits) contains 22 as substring.
Together with 11099969939, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11099969921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5549984970 + 5549984971.
It is an arithmetic number, because the mean of its divisors is an integer number (5549984971).
Almost surely, 211099969941 is an apocalyptic number.
It is an amenable number.
11099969941 is a deficient number, since it is larger than the sum of its proper divisors (1).
11099969941 is an equidigital number, since it uses as much as digits as its factorization.
11099969941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1417176, while the sum is 58.
The spelling of 11099969941 in words is "eleven billion, ninety-nine million, nine hundred sixty-nine thousand, nine hundred forty-one".
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