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111000122100103 is a prime number
BaseRepresentation
bin11001001111010000111010…
…110110010000100110000111
3112120000111201100201112110011
4121033100322312100212013
5104022111222224200403
61032024430243211051
732244331334224555
oct3117207266204607
9476014640645404
10111000122100103
1132405984181765
1210548698376a87
1349c236094aa82
141d5a61268cbd5
15cc757ba46a6d
hex64f43ad90987

111000122100103 has 2 divisors, whose sum is σ = 111000122100104. Its totient is φ = 111000122100102.

The previous prime is 111000122100053. The next prime is 111000122100137. The reversal of 111000122100103 is 301001221000111.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111000122100103 is a prime.

It is a super-3 number, since 3×1110001221001033 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111000122104103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55500061050051 + 55500061050052.

It is an arithmetic number, because the mean of its divisors is an integer number (55500061050052).

Almost surely, 2111000122100103 is an apocalyptic number.

111000122100103 is a deficient number, since it is larger than the sum of its proper divisors (1).

111000122100103 is an equidigital number, since it uses as much as digits as its factorization.

111000122100103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 111000122100103 its reverse (301001221000111), we get a palindrome (412001343100214).

The spelling of 111000122100103 in words is "one hundred eleven trillion, one hundred twenty-two million, one hundred thousand, one hundred three".