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11100100993 is a prime number
BaseRepresentation
bin10100101011001111…
…00001100110000001
31001122120210112222121
422111213201212001
5140213111212433
65033241404241
7542033205322
oct122547414601
931576715877
1011100100993
114786799193
122199499681
13107b8a50c7
147742ca449
1544e763c2d
hex2959e1981

11100100993 has 2 divisors, whose sum is σ = 11100100994. Its totient is φ = 11100100992.

The previous prime is 11100100961. The next prime is 11100100997. The reversal of 11100100993 is 39900100111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5766427969 + 5333673024 = 75937^2 + 73032^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100100993 - 25 = 11100100961 is a prime.

It is not a weakly prime, because it can be changed into another prime (11100100997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550050496 + 5550050497.

It is an arithmetic number, because the mean of its divisors is an integer number (5550050497).

Almost surely, 211100100993 is an apocalyptic number.

It is an amenable number.

11100100993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100100993 is an equidigital number, since it uses as much as digits as its factorization.

11100100993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 25.

The spelling of 11100100993 in words is "eleven billion, one hundred million, one hundred thousand, nine hundred ninety-three".