11100100998053 has 2 divisors, whose sum is σ = 11100100998054. Its totient is φ = 11100100998052.

The previous prime is 11100100997983. The next prime is 11100100998059. The reversal of 11100100998053 is 35089900100111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8561107327969 + 2538993670084 = 2925937^2 + 1593422^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100100998053 - 2²⁸ = 11099832562597 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11100100997998 and 11100100998016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11100100998059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550050499026 + 5550050499027.

It is an arithmetic number, because the mean of its divisors is an integer number (5550050499027).

Almost surely, 2^{11100100998053} is an apocalyptic number.

It is an amenable number.

11100100998053 is a deficient number, since it is larger than the sum of its proper divisors (1).

11100100998053 is an equidigital number, since it uses as much as digits as its factorization.

11100100998053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 38.

The spelling of 11100100998053 in words is "eleven trillion, one hundred billion, one hundred million, nine hundred ninety-eight thousand, fifty-three".