Search a number
-
+
111001220173 is a prime number
BaseRepresentation
bin110011101100000110…
…0000011010001001101
3101121111212101020020201
41213120030003101031
53304312303021143
6122554313213501
711006466542464
oct1473014032115
9347455336221
10111001220173
11430913276a8
121961a101291
13a60ca7358c
14553016b9db
152d49e6a64d
hex19d830344d

111001220173 has 2 divisors, whose sum is σ = 111001220174. Its totient is φ = 111001220172.

The previous prime is 111001220123. The next prime is 111001220219. The reversal of 111001220173 is 371022100111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73364056164 + 37637164009 = 270858^2 + 194003^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111001220173 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111001220173.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111001220123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55500610086 + 55500610087.

It is an arithmetic number, because the mean of its divisors is an integer number (55500610087).

Almost surely, 2111001220173 is an apocalyptic number.

It is an amenable number.

111001220173 is a deficient number, since it is larger than the sum of its proper divisors (1).

111001220173 is an equidigital number, since it uses as much as digits as its factorization.

111001220173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 111001220173 its reverse (371022100111), we get a palindrome (482023320284).

The spelling of 111001220173 in words is "one hundred eleven billion, one million, two hundred twenty thousand, one hundred seventy-three".