Search a number
-
+
111001220219 is a prime number
BaseRepresentation
bin110011101100000110…
…0000011010001111011
3101121111212101020022102
41213120030003101323
53304312303021334
6122554313214015
711006466542561
oct1473014032173
9347455336272
10111001220219
114309132773a
121961a10130b
13a60ca735c6
14553016ba31
152d49e6a67e
hex19d830347b

111001220219 has 2 divisors, whose sum is σ = 111001220220. Its totient is φ = 111001220218.

The previous prime is 111001220173. The next prime is 111001220221. The reversal of 111001220219 is 912022100111.

It is a strong prime.

It is an emirp because it is prime and its reverse (912022100111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111001220219 is a prime.

It is a super-2 number, since 2×1110012202192 (a number of 23 digits) contains 22 as substring.

Together with 111001220221, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111001220219.

It is not a weakly prime, because it can be changed into another prime (111001220249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55500610109 + 55500610110.

It is an arithmetic number, because the mean of its divisors is an integer number (55500610110).

Almost surely, 2111001220219 is an apocalyptic number.

111001220219 is a deficient number, since it is larger than the sum of its proper divisors (1).

111001220219 is an equidigital number, since it uses as much as digits as its factorization.

111001220219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 20.

The spelling of 111001220219 in words is "one hundred eleven billion, one million, two hundred twenty thousand, two hundred nineteen".