Base | Representation |
---|---|
bin | 1010000110000111011110… |
… | …0011001101010001100111 |
3 | 1110022011120002220121010202 |
4 | 2201201313203031101213 |
5 | 2423331203002222413 |
6 | 35335210111141115 |
7 | 2223651222341633 |
oct | 241416743152147 |
9 | 43264502817122 |
10 | 11100201210983 |
11 | 359a629224885 |
12 | 12b3362b1479b |
13 | 62698a823041 |
14 | 2a5377211dc3 |
15 | 143b1d3dbe58 |
hex | a18778cd467 |
11100201210983 has 2 divisors, whose sum is σ = 11100201210984. Its totient is φ = 11100201210982.
The previous prime is 11100201210979. The next prime is 11100201211051. The reversal of 11100201210983 is 38901210200111.
It is a happy number.
11100201210983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11100201210983 - 22 = 11100201210979 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11100201210283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550100605491 + 5550100605492.
It is an arithmetic number, because the mean of its divisors is an integer number (5550100605492).
Almost surely, 211100201210983 is an apocalyptic number.
11100201210983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11100201210983 is an equidigital number, since it uses as much as digits as its factorization.
11100201210983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 29.
The spelling of 11100201210983 in words is "eleven trillion, one hundred billion, two hundred one million, two hundred ten thousand, nine hundred eighty-three".
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