Base | Representation |
---|---|
bin | 110011101100000111… |
… | …1000100101000110101 |
3 | 101121111220212110201112 |
4 | 1213120033010220311 |
5 | 3304313003342323 |
6 | 122554342204405 |
7 | 11006506351601 |
oct | 1473017045065 |
9 | 347456773645 |
10 | 111002012213 |
11 | 43091818784 |
12 | 1961a423705 |
13 | a60cc8cc41 |
14 | 55302d6501 |
15 | 2d4a075178 |
hex | 19d83c4a35 |
111002012213 has 2 divisors, whose sum is σ = 111002012214. Its totient is φ = 111002012212.
The previous prime is 111002012207. The next prime is 111002012243. The reversal of 111002012213 is 312210200111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100528945969 + 10473066244 = 317063^2 + 102338^2 .
It is a cyclic number.
It is not a de Polignac number, because 111002012213 - 214 = 111001995829 is a prime.
It is a super-3 number, since 3×1110020122133 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111002012243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55501006106 + 55501006107.
It is an arithmetic number, because the mean of its divisors is an integer number (55501006107).
Almost surely, 2111002012213 is an apocalyptic number.
It is an amenable number.
111002012213 is a deficient number, since it is larger than the sum of its proper divisors (1).
111002012213 is an equidigital number, since it uses as much as digits as its factorization.
111002012213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 111002012213 its reverse (312210200111), we get a palindrome (423212212324).
The spelling of 111002012213 in words is "one hundred eleven billion, two million, twelve thousand, two hundred thirteen".
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